本文共 980 字，大约阅读时间需要 3 分钟。

class Solution {//compare both the left most and the right most digit, //if not equal return falsepublic:	bool isPalindrome(int x) {		// Start typing your C/C++ solution below		// DO NOT write int main() function		if(x < 0) return false;		int dvsNow = 1;		while(x/dvsNow >= 10)			dvsNow *= 10;		while(x != 0)		{			int l = x/dvsNow;			int r = x%10;			if(l != r) return false;			x = (x%dvsNow)/10;//take off both the left most and the right most digit			dvsNow /= 100;		}		return true;	}};

second time

class Solution {public:    bool isPalindrome(int x) {        // Start typing your C/C++ solution below        // DO NOT write int main() function        if(x < 0) return false;                long long target = x;        //if(target < 0) target = -target;         long long reverse = 0;        long long curNum = target;        while(curNum != 0)        {            reverse = 10*reverse+curNum%10;            curNum /= 10;        }                return reverse == target;    }};

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